02-05-2005, 07:06 AM
ok i have devised a table that indicates what your chance is of getting a certain rune off the countess. the data from d2data.net had helped a lot. i dont have a clue if these values are correct but they are more accurate then the ones from d2data, i dont think d2data.net considered that the countess always drops a rune.
Rune...........d2data.net %.......me %
El...............8.14259499..........21.5748733273379385
Eld.............5.42839666..........14.383248884891959
Tir..............4.52366388..........11.986040728577862
Nef............3.01577592..........7.990693819051908
Eth.............3.16656472..........8.390228520603028
Ith.............2.11104315..........5.5934856892341225
Tal.............2.63880393..........6.9918570916704195
Ral.............1.75920262..........4.661238061113613
Ort............1.84716275..........4.8942999615196625
Thul...........1.23144184..........3.262866658677316
Amn...........1.12882168..........2.990961086123332
Sol.............0.75254779..........1.9939740662476585
Shael.........0.59576700..........1.57856280134205
Dol............0.39717800..........1.0523752008947
Hel............0.30615804..........0.811205879606946
Io..............0.20410536..........0.540803919737964
Lum...........0.15520512.........0.411236320591488
Ko.............0.10347008..........0.274157547060992
Fal.............0.07814147..........0.2070460730187905
Lem...........0.05209431..........0.1380307065137565
Pul............0.03920640..........0.10388249871936
Um............0.02613760..........0.06925499914624
Mal............0.02244255..........0.0594644795654325
Ist.............0.01496170..........0.039642986376955
Gul............0.00008193..........0.0002170842801195
Vex...........0.00005462..........0.000144722853413
Ohm..........0.00004685..........0.0001241352193775
Lo.............0.00003123..........0.0000827479808145
.................37.74110219.......99.9999999979572185 (all the numbers added up)
NOTE: the countess always drops a rune, if she drops one, then my values should be correct, if she drops two my values will be doubled and if she drops 3 the value will be tripled (get my drift). so the logical thing to do would to double my values and the value will be about perfect (becuase the average drop is 2).
Rune...........d2data.net %.......me %
El...............8.14259499..........21.5748733273379385
Eld.............5.42839666..........14.383248884891959
Tir..............4.52366388..........11.986040728577862
Nef............3.01577592..........7.990693819051908
Eth.............3.16656472..........8.390228520603028
Ith.............2.11104315..........5.5934856892341225
Tal.............2.63880393..........6.9918570916704195
Ral.............1.75920262..........4.661238061113613
Ort............1.84716275..........4.8942999615196625
Thul...........1.23144184..........3.262866658677316
Amn...........1.12882168..........2.990961086123332
Sol.............0.75254779..........1.9939740662476585
Shael.........0.59576700..........1.57856280134205
Dol............0.39717800..........1.0523752008947
Hel............0.30615804..........0.811205879606946
Io..............0.20410536..........0.540803919737964
Lum...........0.15520512.........0.411236320591488
Ko.............0.10347008..........0.274157547060992
Fal.............0.07814147..........0.2070460730187905
Lem...........0.05209431..........0.1380307065137565
Pul............0.03920640..........0.10388249871936
Um............0.02613760..........0.06925499914624
Mal............0.02244255..........0.0594644795654325
Ist.............0.01496170..........0.039642986376955
Gul............0.00008193..........0.0002170842801195
Vex...........0.00005462..........0.000144722853413
Ohm..........0.00004685..........0.0001241352193775
Lo.............0.00003123..........0.0000827479808145
.................37.74110219.......99.9999999979572185 (all the numbers added up)
NOTE: the countess always drops a rune, if she drops one, then my values should be correct, if she drops two my values will be doubled and if she drops 3 the value will be tripled (get my drift). so the logical thing to do would to double my values and the value will be about perfect (becuase the average drop is 2).